You know graybo. I ALMOST asked that. Then figured I should ask something I can do
But mathboss has correctly answered the question but mathwhiz got it wrong!
silverberg wrote:Did Silver give a satisfactory response, aclonicy?
Now, have some REAL number magic:
Given the lines L1 and L2, with equations
L1: (x-3)/2 = -2(y+4) = (z+1)/5
L2: (x-6)/2 = -2(y-1) = (z-3)/5
A. Prove that the lines are parallel, and
B. Find the equation of the plane containing the two lines.
blob wrote:What's the indefinite integral of f'(x)=(4)/(4x-6)
silverberg wrote:Given the lines L1 and L2, with equations
L1: (x-3)/2 = -2(y+4) = (z+1)/5
L2: (x-6)/2 = -2(y-1) = (z-3)/5.
radioactivity wrote:Blame NoJo.
mathboss wrote:I think sheep is a middle schooler
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