Come at me math

[blobbydude]

What is Sheep's threat to vote ratio on the reputation tracker, and if sheep threatens me with a vote, what is the probability he goes through with it?

[bleatingsheep39]

What is Sheep's threat to vote ratio on the reputation tracker, and if sheep threatens me with a vote, what is the probability he goes through with it?

So radio is Math boss.

[silverberg]

Am I now the undisputed math genius?

Wonderful.

[radioactivity]

So radio is Math boss.

I'm what now? I know I win lots of forum games but I never even put any effort into this one.

[aclonicy]

What is the indefinite integral of f'(x)=(4x-6)/(4)?

(I just had a quiz on this Thursday)

Edit: Wowee I'm dumb, forgot my rules already. I should have said that
f'(x)=(4)/(4x-6)

Couldn't the problem be solved either way namely, 0.25*x^1(2x^2 - 6x) + c or ln|4x-6|(4x) + c

Or am I just missing something?

[silverberg]

The previous one could be very easily solved by first distributing the 1/4 to make a normal polynomial, then scaling it up. The later has to make use of some obscure division property i've already forgotten. I PMed in an answer long ago, but it deosnt show up in my outbox

[mathwhiz9]

Who's winning?

[blobbydude]

What is the indefinite integral of f'(x)=(4x-6)/(4)?

(I just had a quiz on this Thursday)

Edit: Wowee I'm dumb, forgot my rules already. I should have said that
f'(x)=(4)/(4x-6)

Couldn't the problem be solved either way namely, 0.25*x^1(2x^2 - 6x) + c or ln|4x-6|(4x) + c

Or am I just missing something?

You could do it the first way, but it would be way harder. The answer would just be ln|4x-6| + c. Hopefully I can remember this time becasue I have a test today.

Anybody like related rates? Those are fun.

[silverberg]

Who's winning?

Me, 1-0-0

[bleatingsheep39]

Who's winning?

Me, 1-0-0

SILVERBERG IS MATHBOSS?